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x2-60x-800=0
We add all the numbers together, and all the variables
x^2-60x-800=0
a = 1; b = -60; c = -800;
Δ = b2-4ac
Δ = -602-4·1·(-800)
Δ = 6800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{6800}=\sqrt{400*17}=\sqrt{400}*\sqrt{17}=20\sqrt{17}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-20\sqrt{17}}{2*1}=\frac{60-20\sqrt{17}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+20\sqrt{17}}{2*1}=\frac{60+20\sqrt{17}}{2} $
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