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x2-66x+189=0
We add all the numbers together, and all the variables
x^2-66x+189=0
a = 1; b = -66; c = +189;
Δ = b2-4ac
Δ = -662-4·1·189
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3600}=60$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-66)-60}{2*1}=\frac{6}{2} =3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-66)+60}{2*1}=\frac{126}{2} =63 $
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