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x2-6x-140=0
We add all the numbers together, and all the variables
x^2-6x-140=0
a = 1; b = -6; c = -140;
Δ = b2-4ac
Δ = -62-4·1·(-140)
Δ = 596
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{596}=\sqrt{4*149}=\sqrt{4}*\sqrt{149}=2\sqrt{149}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2\sqrt{149}}{2*1}=\frac{6-2\sqrt{149}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2\sqrt{149}}{2*1}=\frac{6+2\sqrt{149}}{2} $
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