x2-79x+910=0

Solution for x2-79x+910=0 equation:

x2-79x+910=0

We add all the numbers together, and all the variables

x^2-79x+910=0

a = 1; b = -79; c = +910;
Δ = b2-4ac
Δ = -792-4·1·910
Δ = 2601
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2601}=51$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-79)-51}{2*1}=\frac{28}{2}
=14
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-79)+51}{2*1}=\frac{130}{2}
=65
$