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x2-7x=-3
We move all terms to the left:
x2-7x-(-3)=0
We add all the numbers together, and all the variables
x^2-7x+3=0
a = 1; b = -7; c = +3;
Δ = b2-4ac
Δ = -72-4·1·3
Δ = 37
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{37}}{2*1}=\frac{7-\sqrt{37}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{37}}{2*1}=\frac{7+\sqrt{37}}{2} $
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