x2-8x+20=-x2+6x-4

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Solution for x2-8x+20=-x2+6x-4 equation:



x2-8x+20=-x2+6x-4
We move all terms to the left:
x2-8x+20-(-x2+6x-4)=0
We add all the numbers together, and all the variables
-(-1x^2+6x-4)+x2-8x+20=0
We add all the numbers together, and all the variables
x^2-(-1x^2+6x-4)-8x+20=0
We get rid of parentheses
x^2+1x^2-6x-8x+4+20=0
We add all the numbers together, and all the variables
2x^2-14x+24=0
a = 2; b = -14; c = +24;
Δ = b2-4ac
Δ = -142-4·2·24
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-2}{2*2}=\frac{12}{4} =3 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+2}{2*2}=\frac{16}{4} =4 $

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