x2-8x+20=-x2+6x-4

Solution for x2-8x+20=-x2+6x-4 equation:

x2-8x+20=-x2+6x-4

We move all terms to the left:

x2-8x+20-(-x2+6x-4)=0

We add all the numbers together, and all the variables

-(-1x^2+6x-4)+x2-8x+20=0

We add all the numbers together, and all the variables

x^2-(-1x^2+6x-4)-8x+20=0

We get rid of parentheses

x^2+1x^2-6x-8x+4+20=0

We add all the numbers together, and all the variables

2x^2-14x+24=0

a = 2; b = -14; c = +24;
Δ = b2-4ac
Δ = -142-4·2·24
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-2}{2*2}=\frac{12}{4}
=3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+2}{2*2}=\frac{16}{4}
=4
$