x2-8x+25=x(x-4)-25(x-5)-16

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Solution for x2-8x+25=x(x-4)-25(x-5)-16 equation: 



x2-8x+25=x(x-4)-25(x-5)-16

We move all terms to the left:

x2-8x+25-(x(x-4)-25(x-5)-16)=0

We add all the numbers together, and all the variables

x^2-8x-(x(x-4)-25(x-5)-16)+25=0



We calculate terms in parentheses: -(x(x-4)-25(x-5)-16), so:

x(x-4)-25(x-5)-16

We multiply parentheses

x^2-4x-25x+125-16

We add all the numbers together, and all the variables

x^2-29x+109

Back to the equation:

-(x^2-29x+109)



We get rid of parentheses

x^2-x^2-8x+29x-109+25=0

We add all the numbers together, and all the variables

21x-84=0

We move all terms containing x to the left, all other terms to the right

21x=84

x=84/21

x=4

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