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x2-8x=105
We move all terms to the left:
x2-8x-(105)=0
We add all the numbers together, and all the variables
x^2-8x-105=0
a = 1; b = -8; c = -105;
Δ = b2-4ac
Δ = -82-4·1·(-105)
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{484}=22$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-22}{2*1}=\frac{-14}{2} =-7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+22}{2*1}=\frac{30}{2} =15 $
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