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x2-8x=72
We move all terms to the left:
x2-8x-(72)=0
We add all the numbers together, and all the variables
x^2-8x-72=0
a = 1; b = -8; c = -72;
Δ = b2-4ac
Δ = -82-4·1·(-72)
Δ = 352
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:x_{1}=\frac{-b-\sqrt{\Delta}}{2a}x_{2}=\frac{-b+\sqrt{\Delta}}{2a}
The end solution:
\sqrt{\Delta}=\sqrt{352}=\sqrt{16*22}=\sqrt{16}*\sqrt{22}=4\sqrt{22}x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-4\sqrt{22}}{2*1}=\frac{8-4\sqrt{22}}{2}x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+4\sqrt{22}}{2*1}=\frac{8+4\sqrt{22}}{2}
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