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x2-95=14x
We move all terms to the left:
x2-95-(14x)=0
We add all the numbers together, and all the variables
x^2-14x-95=0
a = 1; b = -14; c = -95;
Δ = b2-4ac
Δ = -142-4·1·(-95)
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{576}=24$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-24}{2*1}=\frac{-10}{2} =-5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+24}{2*1}=\frac{38}{2} =19 $
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