x2-96x+1980=0

Solution for x2-96x+1980=0 equation:

x2-96x+1980=0

We add all the numbers together, and all the variables

x^2-96x+1980=0

a = 1; b = -96; c = +1980;
Δ = b2-4ac
Δ = -962-4·1·1980
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-96)-36}{2*1}=\frac{60}{2}
=30
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-96)+36}{2*1}=\frac{132}{2}
=66
$