x2-9=(x-3)(x-5)

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Solution for x2-9=(x-3)(x-5) equation: 



x2-9=(x-3)(x-5)

We move all terms to the left:

x2-9-((x-3)(x-5))=0

We add all the numbers together, and all the variables

x^2-((x-3)(x-5))-9=0

We multiply parentheses ..

x^2-((+x^2-5x-3x+15))-9=0



We calculate terms in parentheses: -((+x^2-5x-3x+15)), so:

(+x^2-5x-3x+15)

We get rid of parentheses

x^2-5x-3x+15

We add all the numbers together, and all the variables

x^2-8x+15

Back to the equation:

-(x^2-8x+15)



We get rid of parentheses

x^2-x^2+8x-15-9=0

We add all the numbers together, and all the variables

8x-24=0

We move all terms containing x to the left, all other terms to the right

8x=24

x=24/8

x=3

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