x2-x+15=(x-3)(x-5)

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Solution for x2-x+15=(x-3)(x-5) equation: 



x2-x+15=(x-3)(x-5)

We move all terms to the left:

x2-x+15-((x-3)(x-5))=0

We add all the numbers together, and all the variables

x^2-1x-((x-3)(x-5))+15=0

We multiply parentheses ..

x^2-((+x^2-5x-3x+15))-1x+15=0



We calculate terms in parentheses: -((+x^2-5x-3x+15)), so:

(+x^2-5x-3x+15)

We get rid of parentheses

x^2-5x-3x+15

We add all the numbers together, and all the variables

x^2-8x+15

Back to the equation:

-(x^2-8x+15)



We add all the numbers together, and all the variables

x^2-1x-(x^2-8x+15)+15=0

We get rid of parentheses

x^2-x^2-1x+8x-15+15=0

We add all the numbers together, and all the variables

7x=0

x=0/7

x=0

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