If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x2-x-12=0
We add all the numbers together, and all the variables
x^2-1x-12=0
a = 1; b = -1; c = -12;
Δ = b2-4ac
Δ = -12-4·1·(-12)
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-7}{2*1}=\frac{-6}{2} =-3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+7}{2*1}=\frac{8}{2} =4 $
| 36=6b/2 | | 2(5-3x)=x-4(3-x | | 1/7a=21/2 | | 10^2+y^2=144 | | x+97=31 | | 2(3m+3)-6=36 | | 2-(9-u)2+u=-50 | | x+|x|=0 | | 15x^2-6x-10=0 | | 2(b-5)+7b-8=-10-2(b+7) | | 27x+2=11x-4+70 | | X2+y2=144 | | 9y-45=-9(y-7) | | 2x-2x+7=5x-2x-23 | | 0=-3b-4b | | x+14=67 | | .12=2(x)^2+(20/x) | | 48+2*p=10p | | x+28=27 | | 3÷4(x-6)=12 | | 12=w−|−7| | | (4^x)*(3^(2x))=6 | | Z/6+5=7-z/6 | | 3x-2=30x+7 | | 24-5m=34 | | 3.5=x+8.4 | | 3x=(1÷3)(50-x) | | 1/4×+18=x | | (r−7)=1 | | 11x-1(x+5)=x | | 3x-15+5x+49=90 | | y−3.4=-12.7 |