x2/3+x+x2/3+x=290

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Solution for x2/3+x+x2/3+x=290 equation: 


x in (-oo:+oo)

(x^2)/3+(x^2)/3+x+x = 290 // - 290

(x^2)/3+(x^2)/3+x+x-290 = 0

2/3*x^2+2*x-290 = 0

DELTA = 2^2-(-290*2/3*4)

DELTA = 2332/3

DELTA > 0

x = ((2332/3)^(1/2)-2)/(2/3*2) or x = (-(2332/3)^(1/2)-2)/(2/3*2)

x = 3/4*((2332/3)^(1/2)-2) or x = -3/4*((2332/3)^(1/2)+2)

x in { -3/4*((2332/3)^(1/2)+2), 3/4*((2332/3)^(1/2)-2) }

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