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x2/3+x=50
We move all terms to the left:
x2/3+x-(50)=0
We add all the numbers together, and all the variables
x+x2/3-50=0
We multiply all the terms by the denominator
x*3+x2-50*3=0
We add all the numbers together, and all the variables
x^2+x*3-150=0
Wy multiply elements
x^2+3x-150=0
a = 1; b = 3; c = -150;
Δ = b2-4ac
Δ = 32-4·1·(-150)
Δ = 609
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{609}}{2*1}=\frac{-3-\sqrt{609}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{609}}{2*1}=\frac{-3+\sqrt{609}}{2} $
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