x2=(4-8x1)/6

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Solution for x2=(4-8x1)/6 equation: 


x in (-oo:+oo)

x^2 = (4-(8*x^1))/6 // - (4-(8*x^1))/6

x^2-((4-(8*x^1))/6) = 0

x^2-((4-8*x)/6) = 0

(-1*(4-8*x))/6+x^2 = 0

(-1*(4-8*x))/6+(6*x^2)/6 = 0

6*x^2-1*(4-8*x) = 0

6*x^2+8*x-4 = 0

6*x^2+8*x-4 = 0

2*(3*x^2+4*x-2) = 0

3*x^2+4*x-2 = 0

DELTA = 4^2-(-2*3*4)

DELTA = 40

DELTA > 0

x = (40^(1/2)-4)/(2*3) or x = (-40^(1/2)-4)/(2*3)

x = (2*10^(1/2)-4)/6 or x = (-2*10^(1/2)-4)/6

2*(x-((-2*10^(1/2)-4)/6))*(x-((2*10^(1/2)-4)/6)) = 0

(2*(x-((-2*10^(1/2)-4)/6))*(x-((2*10^(1/2)-4)/6)))/6 = 0

(2*(x-((-2*10^(1/2)-4)/6))*(x-((2*10^(1/2)-4)/6)))/6 = 0 // * 6

2*(x-((-2*10^(1/2)-4)/6))*(x-((2*10^(1/2)-4)/6)) = 0

( 2 )

2 = 0

x belongs to the empty set

( x-((-2*10^(1/2)-4)/6) )

x-((-2*10^(1/2)-4)/6) = 0 // + (-2*10^(1/2)-4)/6

x = (-2*10^(1/2)-4)/6

( x-((2*10^(1/2)-4)/6) )

x-((2*10^(1/2)-4)/6) = 0 // + (2*10^(1/2)-4)/6

x = (2*10^(1/2)-4)/6

x in { (-2*10^(1/2)-4)/6, (2*10^(1/2)-4)/6 }

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