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x2=10/16
We move all terms to the left:
x2-(10/16)=0
We add all the numbers together, and all the variables
x2-(+10/16)=0
We add all the numbers together, and all the variables
x^2-(+10/16)=0
We get rid of parentheses
x^2-10/16=0
We multiply all the terms by the denominator
x^2*16-10=0
Wy multiply elements
16x^2-10=0
a = 16; b = 0; c = -10;
Δ = b2-4ac
Δ = 02-4·16·(-10)
Δ = 640
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{640}=\sqrt{64*10}=\sqrt{64}*\sqrt{10}=8\sqrt{10}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{10}}{2*16}=\frac{0-8\sqrt{10}}{32} =-\frac{8\sqrt{10}}{32} =-\frac{\sqrt{10}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{10}}{2*16}=\frac{0+8\sqrt{10}}{32} =\frac{8\sqrt{10}}{32} =\frac{\sqrt{10}}{4} $
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