x2=10x-41

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Solution for x2=10x-41 equation: 



x2=10x-41

We move all terms to the left:

x2-(10x-41)=0

We add all the numbers together, and all the variables

x^2-(10x-41)=0

We get rid of parentheses

x^2-10x+41=0

a = 1; b = -10; c = +41;
Δ = b2-4ac
Δ = -102-4·1·41
Δ = -64
Delta is less than zero, so there is no solution for the equation

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