x2=12x+27

Solution for x2=12x+27 equation:

x2=12x+27

We move all terms to the left:

x2-(12x+27)=0

We add all the numbers together, and all the variables

x^2-(12x+27)=0

We get rid of parentheses

x^2-12x-27=0

a = 1; b = -12; c = -27;
Δ = b2-4ac
Δ = -122-4·1·(-27)
Δ = 252
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{252}=\sqrt{36*7}=\sqrt{36}*\sqrt{7}=6\sqrt{7}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-6\sqrt{7}}{2*1}=\frac{12-6\sqrt{7}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+6\sqrt{7}}{2*1}=\frac{12+6\sqrt{7}}{2}
$