x2=16+((x-4)(x+4))

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Solution for x2=16+((x-4)(x+4)) equation: 



x2=16+((x-4)(x+4))

We move all terms to the left:

x2-(16+((x-4)(x+4)))=0

We add all the numbers together, and all the variables

x^2-(16+((x-4)(x+4)))=0

We use the square of the difference formula

x^2+x^2+16=0

We add all the numbers together, and all the variables

2x^2+16=0

a = 2; b = 0; c = +16;
Δ = b2-4ac
Δ = 02-4·2·16
Δ = -128
Delta is less than zero, so there is no solution for the equation

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