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x2=16/3
We move all terms to the left:
x2-(16/3)=0
We add all the numbers together, and all the variables
x2-(+16/3)=0
We add all the numbers together, and all the variables
x^2-(+16/3)=0
We get rid of parentheses
x^2-16/3=0
We multiply all the terms by the denominator
x^2*3-16=0
Wy multiply elements
3x^2-16=0
a = 3; b = 0; c = -16;
Δ = b2-4ac
Δ = 02-4·3·(-16)
Δ = 192
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{192}=\sqrt{64*3}=\sqrt{64}*\sqrt{3}=8\sqrt{3}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{3}}{2*3}=\frac{0-8\sqrt{3}}{6} =-\frac{8\sqrt{3}}{6} =-\frac{4\sqrt{3}}{3} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{3}}{2*3}=\frac{0+8\sqrt{3}}{6} =\frac{8\sqrt{3}}{6} =\frac{4\sqrt{3}}{3} $
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