x2=19+3x

Solution for x2=19+3x equation:

x2=19+3x

We move all terms to the left:

x2-(19+3x)=0

We add all the numbers together, and all the variables

x2-(3x+19)=0

We add all the numbers together, and all the variables

x^2-(3x+19)=0

We get rid of parentheses

x^2-3x-19=0

a = 1; b = -3; c = -19;
Δ = b2-4ac
Δ = -32-4·1·(-19)
Δ = 85
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{85}}{2*1}=\frac{3-\sqrt{85}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{85}}{2*1}=\frac{3+\sqrt{85}}{2}
$