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x2=2160
We move all terms to the left:
x2-(2160)=0
We add all the numbers together, and all the variables
x^2-2160=0
a = 1; b = 0; c = -2160;
Δ = b2-4ac
Δ = 02-4·1·(-2160)
Δ = 8640
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{8640}=\sqrt{576*15}=\sqrt{576}*\sqrt{15}=24\sqrt{15}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-24\sqrt{15}}{2*1}=\frac{0-24\sqrt{15}}{2} =-\frac{24\sqrt{15}}{2} =-12\sqrt{15} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+24\sqrt{15}}{2*1}=\frac{0+24\sqrt{15}}{2} =\frac{24\sqrt{15}}{2} =12\sqrt{15} $
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