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x2=2500
We move all terms to the left:
x2-(2500)=0
We add all the numbers together, and all the variables
x^2-2500=0
a = 1; b = 0; c = -2500;
Δ = b2-4ac
Δ = 02-4·1·(-2500)
Δ = 10000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{10000}=100$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-100}{2*1}=\frac{-100}{2} =-50 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+100}{2*1}=\frac{100}{2} =50 $
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