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x2=27x-90
We move all terms to the left:
x2-(27x-90)=0
We add all the numbers together, and all the variables
x^2-(27x-90)=0
We get rid of parentheses
x^2-27x+90=0
a = 1; b = -27; c = +90;
Δ = b2-4ac
Δ = -272-4·1·90
Δ = 369
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{369}=\sqrt{9*41}=\sqrt{9}*\sqrt{41}=3\sqrt{41}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-3\sqrt{41}}{2*1}=\frac{27-3\sqrt{41}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+3\sqrt{41}}{2*1}=\frac{27+3\sqrt{41}}{2} $
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