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x2=2809
We move all terms to the left:
x2-(2809)=0
We add all the numbers together, and all the variables
x^2-2809=0
a = 1; b = 0; c = -2809;
Δ = b2-4ac
Δ = 02-4·1·(-2809)
Δ = 11236
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{11236}=106$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-106}{2*1}=\frac{-106}{2} =-53 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+106}{2*1}=\frac{106}{2} =53 $
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