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x2=2x-15=0
We move all terms to the left:
x2-(2x-15)=0
We add all the numbers together, and all the variables
x^2-(2x-15)=0
We get rid of parentheses
x^2-2x+15=0
a = 1; b = -2; c = +15;
Δ = b2-4ac
Δ = -22-4·1·15
Δ = -56
Delta is less than zero, so there is no solution for the equation
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