x2=4(10)

Solution for x2=4(10) equation:

x2=4(10)

We move all terms to the left:

x2-(4(10))=0

determiningTheFunctionDomain
x2-410=0

We add all the numbers together, and all the variables

x^2-410=0

a = 1; b = 0; c = -410;
Δ = b2-4ac
Δ = 02-4·1·(-410)
Δ = 1640
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1640}=\sqrt{4*410}=\sqrt{4}*\sqrt{410}=2\sqrt{410}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{410}}{2*1}=\frac{0-2\sqrt{410}}{2}
=-\frac{2\sqrt{410}}{2}
=-\sqrt{410}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{410}}{2*1}=\frac{0+2\sqrt{410}}{2}
=\frac{2\sqrt{410}}{2}
=\sqrt{410}
$