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x2=425
We move all terms to the left:
x2-(425)=0
We add all the numbers together, and all the variables
x^2-425=0
a = 1; b = 0; c = -425;
Δ = b2-4ac
Δ = 02-4·1·(-425)
Δ = 1700
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1700}=\sqrt{100*17}=\sqrt{100}*\sqrt{17}=10\sqrt{17}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10\sqrt{17}}{2*1}=\frac{0-10\sqrt{17}}{2} =-\frac{10\sqrt{17}}{2} =-5\sqrt{17} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10\sqrt{17}}{2*1}=\frac{0+10\sqrt{17}}{2} =\frac{10\sqrt{17}}{2} =5\sqrt{17} $
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