x2=4936

Solution for x2=4936 equation:

x2=4936

We move all terms to the left:

x2-(4936)=0

We add all the numbers together, and all the variables

x^2-4936=0

a = 1; b = 0; c = -4936;
Δ = b2-4ac
Δ = 02-4·1·(-4936)
Δ = 19744
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{19744}=\sqrt{16*1234}=\sqrt{16}*\sqrt{1234}=4\sqrt{1234}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{1234}}{2*1}=\frac{0-4\sqrt{1234}}{2}
=-\frac{4\sqrt{1234}}{2}
=-2\sqrt{1234}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{1234}}{2*1}=\frac{0+4\sqrt{1234}}{2}
=\frac{4\sqrt{1234}}{2}
=2\sqrt{1234}
$