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x2=529
We move all terms to the left:
x2-(529)=0
We add all the numbers together, and all the variables
x^2-529=0
a = 1; b = 0; c = -529;
Δ = b2-4ac
Δ = 02-4·1·(-529)
Δ = 2116
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2116}=46$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-46}{2*1}=\frac{-46}{2} =-23 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+46}{2*1}=\frac{46}{2} =23 $
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