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x2=625
We move all terms to the left:
x2-(625)=0
We add all the numbers together, and all the variables
x^2-625=0
a = 1; b = 0; c = -625;
Δ = b2-4ac
Δ = 02-4·1·(-625)
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2500}=50$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-50}{2*1}=\frac{-50}{2} =-25 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+50}{2*1}=\frac{50}{2} =25 $
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