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x2=853
We move all terms to the left:
x2-(853)=0
We add all the numbers together, and all the variables
x^2-853=0
a = 1; b = 0; c = -853;
Δ = b2-4ac
Δ = 02-4·1·(-853)
Δ = 3412
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3412}=\sqrt{4*853}=\sqrt{4}*\sqrt{853}=2\sqrt{853}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{853}}{2*1}=\frac{0-2\sqrt{853}}{2} =-\frac{2\sqrt{853}}{2} =-\sqrt{853} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{853}}{2*1}=\frac{0+2\sqrt{853}}{2} =\frac{2\sqrt{853}}{2} =\sqrt{853} $
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