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x2=9/400
We move all terms to the left:
x2-(9/400)=0
We add all the numbers together, and all the variables
x2-(+9/400)=0
We add all the numbers together, and all the variables
x^2-(+9/400)=0
We get rid of parentheses
x^2-9/400=0
We multiply all the terms by the denominator
x^2*400-9=0
Wy multiply elements
400x^2-9=0
a = 400; b = 0; c = -9;
Δ = b2-4ac
Δ = 02-4·400·(-9)
Δ = 14400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{14400}=120$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-120}{2*400}=\frac{-120}{800} =-3/20 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+120}{2*400}=\frac{120}{800} =3/20 $
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