x3+4x=2/3(6x+12)

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Solution for x3+4x=2/3(6x+12) equation:



x3+4x=2/3(6x+12)
We move all terms to the left:
x3+4x-(2/3(6x+12))=0
Domain of the equation: 3(6x+12))!=0
x∈R
We add all the numbers together, and all the variables
x^3+4x-(2/3(6x+12))=0
We multiply all the terms by the denominator
x^3*3(6x+12))+4x*3(6x+12))-(2=0
We do not support expression: x^3

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