x3/2-(4+x)1/2=-5

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Solution for x3/2-(4+x)1/2=-5 equation: 


x in (-oo:+oo)

(x^3)/2-(((x+4)^1)/2) = -5 // + 5

(x^3)/2-(((x+4)^1)/2)+5 = 0

(x^3)/2-((x+4)/2)+5 = 0

(-1*(x+4))/2+(x^3)/2+5 = 0

(-1*(x+4))/2+(x^3)/2+(2*5)/2 = 0

x^3-1*(x+4)+2*5 = 0

x^3-x-4+10 = 0

x^3-x+6 = 0

x^3-x+6 = 0

x^3-x+6 = 0

{ 1, -1, 2, -2, 3, -3, 6, -6 }

1

x = 1

x^3-x+6 = 6

1

-1

x = -1

x^3-x+6 = 6

-1

2

x = 2

x^3-x+6 = 12

2

-2

x = -2

x^3-x+6 = 0

-2

x+2

x^2-2*x+3

x^3-x+6

x+2

-x^3-2*x^2

6-2*x^2-x

2*x^2+4*x

3*x+6

-3*x-6

0

x^2-2*x+3 = 0

DELTA = (-2)^2-(1*3*4)

DELTA = -8

DELTA < 0

x in { -2} 

x+2 = 0

(x+2)/2 = 0

(x+2)/2 = 0 // * 2

x+2 = 0

x+2 = 0 // - 2

x = -2

x = -2

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