x4-12(6-x)=7x+3(6-2x)-1

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Solution for x4-12(6-x)=7x+3(6-2x)-1 equation: 



x4-12(6-x)=7x+3(6-2x)-1

We move all terms to the left:

x4-12(6-x)-(7x+3(6-2x)-1)=0

We add all the numbers together, and all the variables

x4-12(-1x+6)-(7x+3(-2x+6)-1)=0

We add all the numbers together, and all the variables

x^4-12(-1x+6)-(7x+3(-2x+6)-1)=0

We multiply parentheses

x^4+12x-(7x+3(-2x+6)-1)-72=0



We calculate terms in parentheses: -(7x+3(-2x+6)-1), so:

7x+3(-2x+6)-1

We multiply parentheses

7x-6x+18-1

We add all the numbers together, and all the variables

x+17

Back to the equation:

-(x+17)



We do not support expression: x^4

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