x;-4/5x=-20

Solution for x;-4/5x=-20 equation:

x-4/5x=-20

We move all terms to the left:

x-4/5x-(-20)=0


Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R


We add all the numbers together, and all the variables

x-4/5x+20=0

We multiply all the terms by the denominator


x*5x+20*5x-4=0

Wy multiply elements

5x^2+100x-4=0

a = 5; b = 100; c = -4;
Δ = b2-4ac
Δ = 1002-4·5·(-4)
Δ = 10080
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{10080}=\sqrt{144*70}=\sqrt{144}*\sqrt{70}=12\sqrt{70}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(100)-12\sqrt{70}}{2*5}=\frac{-100-12\sqrt{70}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(100)+12\sqrt{70}}{2*5}=\frac{-100+12\sqrt{70}}{10}
$