If it's not what You are looking for type in the equation solver your own equation and let us solve it.
1/((cos(x))^4)
516;23
0;143;0;3;0;0
3*y+14 = 20
C/2-4 = 1
| 2+y+4y=124 | | 14-3(w-10)=2 | | 2x^2-8x+4=12 | | (10*56)+(6.25*167)-(5*27)+5= | | 2a+a=126 | | C/2-4=1 | | 5(4+x)=2(6x-11) | | A/-8-3=2 | | 3/4x=-1/3 | | 3/4=x/60 | | 2-(c+4)=16 | | 2(x+4)=6(3x+4) | | 3r(r-2)= | | 4(x-1)=x+2 | | 6x+238=3x+170 | | x/3=x/2-4 | | Tanx=9/6 | | 2x-8=4-8x | | r^2=-7r-12 | | 1/1/6=2/1/8y-10 | | y=14x+49 | | 7d-7=8d+2 | | 3c-15=5c+1 | | w/4-3/20=w/5 | | 2(3-x)=-(x+7) | | x+.19x=20.3 | | 3x+16=24-2x | | 2x^2-5y^2=n | | 4.5+2.25x=31.5 | | 7r-3+r=69 | | x^2+2x-3=-36 | | 2(3-x)=(x+7) |