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x=(20-x)(300+68x)
We move all terms to the left:
x-((20-x)(300+68x))=0
We add all the numbers together, and all the variables
x-((-1x+20)(68x+300))=0
We multiply parentheses ..
-((-68x^2-300x+1360x+6000))+x=0
We calculate terms in parentheses: -((-68x^2-300x+1360x+6000)), so:We get rid of parentheses
(-68x^2-300x+1360x+6000)
We get rid of parentheses
-68x^2-300x+1360x+6000
We add all the numbers together, and all the variables
-68x^2+1060x+6000
Back to the equation:
-(-68x^2+1060x+6000)
68x^2-1060x+x-6000=0
We add all the numbers together, and all the variables
68x^2-1059x-6000=0
a = 68; b = -1059; c = -6000;
Δ = b2-4ac
Δ = -10592-4·68·(-6000)
Δ = 2753481
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1059)-\sqrt{2753481}}{2*68}=\frac{1059-\sqrt{2753481}}{136} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1059)+\sqrt{2753481}}{2*68}=\frac{1059+\sqrt{2753481}}{136} $
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