x=(2x+3)(4x+7)

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Solution for x=(2x+3)(4x+7) equation: 



x=(2x+3)(4x+7)

We move all terms to the left:

x-((2x+3)(4x+7))=0

We multiply parentheses ..

-((+8x^2+14x+12x+21))+x=0



We calculate terms in parentheses: -((+8x^2+14x+12x+21)), so:

(+8x^2+14x+12x+21)

We get rid of parentheses

8x^2+14x+12x+21

We add all the numbers together, and all the variables

8x^2+26x+21

Back to the equation:

-(8x^2+26x+21)



We add all the numbers together, and all the variables

x-(8x^2+26x+21)=0

We get rid of parentheses

-8x^2+x-26x-21=0

We add all the numbers together, and all the variables

-8x^2-25x-21=0

a = -8; b = -25; c = -21;
Δ = b2-4ac
Δ = -252-4·(-8)·(-21)
Δ = -47
Delta is less than zero, so there is no solution for the equation

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