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x=(2x+5/2)-3x.
We move all terms to the left:
x-((2x+5/2)-3x.)=0
Domain of the equation: 2)-3x.)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
x-((+2x+5/2)-3x.)=0
We multiply all the terms by the denominator
x*2)-3x.)-((+2x+5=0
We add all the numbers together, and all the variables
2x+x*2)-3x.)-((+5=0
Wy multiply elements
2x^2+2x+5=0
a = 2; b = 2; c = +5;
Δ = b2-4ac
Δ = 22-4·2·5
Δ = -36
Delta is less than zero, so there is no solution for the equation
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