x=(2x-16)(x+6)

Solution for x=(2x-16)(x+6) equation:

x=(2x-16)(x+6)

We move all terms to the left:

x-((2x-16)(x+6))=0

We multiply parentheses ..

-((+2x^2+12x-16x-96))+x=0


We calculate terms in parentheses: -((+2x^2+12x-16x-96)), so:

(+2x^2+12x-16x-96)

We get rid of parentheses

2x^2+12x-16x-96

We add all the numbers together, and all the variables

2x^2-4x-96

Back to the equation:

-(2x^2-4x-96)


We add all the numbers together, and all the variables

x-(2x^2-4x-96)=0

We get rid of parentheses

-2x^2+x+4x+96=0

We add all the numbers together, and all the variables

-2x^2+5x+96=0

a = -2; b = 5; c = +96;
Δ = b2-4ac
Δ = 52-4·(-2)·96
Δ = 793
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{793}}{2*-2}=\frac{-5-\sqrt{793}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{793}}{2*-2}=\frac{-5+\sqrt{793}}{-4}
$