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x=(3x-5)+(2x-5)
We move all terms to the left:
x-((3x-5)+(2x-5))=0
We calculate terms in parentheses: -((3x-5)+(2x-5)), so:We get rid of parentheses
(3x-5)+(2x-5)
We get rid of parentheses
3x+2x-5-5
We add all the numbers together, and all the variables
5x-10
Back to the equation:
-(5x-10)
x-5x+10=0
We add all the numbers together, and all the variables
-4x+10=0
We move all terms containing x to the left, all other terms to the right
-4x=-10
x=-10/-4
x=2+1/2
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