x=(7x-15)+(x+28)+(4x-3)

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Solution for x=(7x-15)+(x+28)+(4x-3) equation: 



x=(7x-15)+(x+28)+(4x-3)

We move all terms to the left:

x-((7x-15)+(x+28)+(4x-3))=0



We calculate terms in parentheses: -((7x-15)+(x+28)+(4x-3)), so:

(7x-15)+(x+28)+(4x-3)

We get rid of parentheses

7x+x+4x-15+28-3

We add all the numbers together, and all the variables

12x+10

Back to the equation:

-(12x+10)



We get rid of parentheses

x-12x-10=0

We add all the numbers together, and all the variables

-11x-10=0

We move all terms containing x to the left, all other terms to the right

-11x=10

x=10/-11

x=-10/11

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