x=(7x/5)+9=23

Solution for x=(7x/5)+9=23 equation:

x=(7x/5)+9=23

We move all terms to the left:

x-((7x/5)+9)=0

We add all the numbers together, and all the variables

x-((+7x/5)+9)=0

We multiply all the terms by the denominator


x*5)+9)-((+7x=0

We add all the numbers together, and all the variables

7x+x*5)+9)-((=0

Wy multiply elements

5x^2+7x=0

a = 5; b = 7; c = 0;
Δ = b2-4ac
Δ = 72-4·5·0
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-7}{2*5}=\frac{-14}{10}
=-1+2/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+7}{2*5}=\frac{0}{10}
=0
$