x=(x-1,5)+(x+2)(x-2)-10

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Solution for x=(x-1,5)+(x+2)(x-2)-10 equation: 



x=(x-1.5)+(x+2)(x-2)-10

We move all terms to the left:

x-((x-1.5)+(x+2)(x-2)-10)=0

We use the square of the difference formula

x^2+x+4=0

a = 1; b = 1; c = +4;
Δ = b2-4ac
Δ = 12-4·1·4
Δ = -15
Delta is less than zero, so there is no solution for the equation

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