x=-(x-11)(x+3)

Solution for x=-(x-11)(x+3) equation:

x=-(x-11)(x+3)

We move all terms to the left:

x-(-(x-11)(x+3))=0

We multiply parentheses ..

-(-(+x^2+3x-11x-33))+x=0


We calculate terms in parentheses: -(-(+x^2+3x-11x-33)), so:

-(+x^2+3x-11x-33)

We get rid of parentheses

-x^2-3x+11x+33

We add all the numbers together, and all the variables

-1x^2+8x+33

Back to the equation:

-(-1x^2+8x+33)


We get rid of parentheses

1x^2-8x+x-33=0

We add all the numbers together, and all the variables

x^2-7x-33=0

a = 1; b = -7; c = -33;
Δ = b2-4ac
Δ = -72-4·1·(-33)
Δ = 181
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{181}}{2*1}=\frac{7-\sqrt{181}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{181}}{2*1}=\frac{7+\sqrt{181}}{2}
$