x=-0.45(x+1.33)(x-5)

Solution for x=-0.45(x+1.33)(x-5) equation:

x=-0.45(x+1.33)(x-5)

We move all terms to the left:

x-(-0.45(x+1.33)(x-5))=0

We multiply parentheses ..

-(-0.45(+x^2-5x+1.33x-6.65))+x=0


We calculate terms in parentheses: -(-0.45(+x^2-5x+1.33x-6.65)), so:

-0.45(+x^2-5x+1.33x-6.65)

We multiply parentheses

-0.45x^2+2.25x-0.45x+2.9925

We add all the numbers together, and all the variables

-0.45x^2+1.8x+2.9925

Back to the equation:

-(-0.45x^2+1.8x+2.9925)


We get rid of parentheses

0.45x^2-1.8x+x-2.9925=0

We add all the numbers together, and all the variables

0.45x^2-0.8x-2.9925=0

a = 0.45; b = -0.8; c = -2.9925;
Δ = b2-4ac
Δ = -0.82-4·0.45·(-2.9925)
Δ = 6.0265
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.8)-\sqrt{6.0265}}{2*0.45}=\frac{0.8-\sqrt{6.0265}}{0.9}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.8)+\sqrt{6.0265}}{2*0.45}=\frac{0.8+\sqrt{6.0265}}{0.9}
$